How do you solve $\sqrt{x} + 1 = 5$ $sqrt(x) + 1=5$ ?

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Answer 1 · 2017-05-30T18:26:57

See a solution process below:

First, subtract $1$ $color(red)(1)$ from each side of the equation to isolate the radical while keeping the equation balanced:

$\sqrt{x} + 1 - 1 = 5 - 1$ $sqrt(x) + 1 - color(red)(1) = 5 - color(red)(1)$

$\sqrt{x} + 0 = 4$ $sqrt(x) + 0 = 4$

$\sqrt{x} = 4$ $sqrt(x) = 4$

Now, square each side of the equation to solve for $x$ $x$ while keeping the equation balanced:

${(\sqrt{x})}^{2} = 4^{2}$ $(sqrt(x))^2 = 4^2$

$x = 16$ $x = 16$

How do you solve sqrt(x) + 1=5√x+1=5sqrt(x) + 1=5?