How do you solve #sqrt(k+9)-sqrtk=sqrt3#?

Related questions

• How do you solve radical equations?
• What are Radical Equations?
• How do you solve radical equations with cube roots?
• How do you find extraneous solutions when solving radical equations?
• How do you solve #\sqrt{x+15}=\sqrt{3x-3}#?
• How do you solve and find the extraneous solutions for #2\sqrt{4-3x}+3=0#?
• How do you solve #\sqrt{x^2-5x}-6=0#?
• How do you solve #\sqrt{x}=x-6#?
• How do you solve for x in #""^3sqrt(-2-5x)+3=0#?
• How do you solve for x in #sqrt(42-x)+x =13#?