How do you solve $sqrt(9-b)=sqrt(1-9b)$ ?

Question

3211 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-12T00:04:46

$b = - 1$

We have: $sqrt(9 - b) = sqrt(1 - 9 b)$

Let's square both sides of the equation:

$Rightarrow (sqrt(9 - b))^(2) = (sqrt(1 - 9 b))^(2)$

$Rightarrow 9 - b = 1 - 9 b$

Then, let's add $9 b$ to both sides:

$Rightarrow 9 - b + 9 b = 1 - 9 b + 9 b$

$Rightarrow 9 + 8 b = 1$

Now, let's subtract $9$ from both sides:

$Rightarrow 9 + 8 b - 8 = 1 - 9$

$Rightarrow 8 b = - 8$

Finally, to solve for $b$ , let's divide both sides by $8$ :

$Rightarrow frac(8 b)(8) = - frac(8)(8)$

$therefore b = - 1$

Therefore, the solution to the equation is $b = - 1$ .

How do you solve sqrt(9-b)=sqrt(1-9b)sqrt(9-b)=sqrt(1-9b)?