How do you solve $\sqrt{8 x} + 3 = 7$ $sqrt(8x) + 3 = 7$ ?

Question

1633 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-21T07:45:04

$x = 2$ $x=2$

Given-
$\sqrt{8 x} + 3 = 7$ $sqrt(8x)+3=7$

[Add $- 3$ $-3$ on both sides]

$\sqrt{8 x} + 3 - 3 = 7 - 3$ $sqrt(8x)+3-3=7-3$

$\sqrt{8 x} = 4$ $sqrt(8x)=4$

Square both sides

$8 x = 16$ $8x=16$
$x = \frac{16}{8} = 2$ $x=16/8=2$

How do you solve √8x+3=7 sqrt(8x) + 3 = 7?