How do you solve $sqrt(-8-2a)=0$ ?

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Answer 1 · 2017-03-06T00:45:41

See the entire solution process below:

First, square the expression on each side of the equation:

$(sqrt(-8 - 2a))^2 = 0^2$

$-8 - 2a = 0$

Next, add $color(red)(8)$ to each side of the equation to isolate the $a$ term while keeping the equation balanced:

$color(red)(8) - 8 - 2a = color(red)(8) + 0$

$0 - 2a = 8$

$-2a = 8$

Now, divide each side of the equation by $color(red)(-2)$ to solve for $a$ while keeping the equation balanced:

$(-2a)/color(red)(-2) = 8/color(red)(-2)$

$(color(red)(cancel(color(black)(-2)))a)/cancel(color(red)(-2)) = -4$

$a = -4$

How do you solve sqrt(-8-2a)=0sqrt(-8-2a)=0?