How do you solve $sqrt(7x-4)=13$ ?

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Answer 1 · 2017-05-08T13:07:30

$7x-4=169$ or $x=173/7$

Get rid of square root of the first term by taking 2nd power of both sides:

Now you will have

${(7x-4)^0.5}^2=13^2$

$7x-4=13*13$

$7x=169+4$

$7x=173$

$x=173/7$

This is your answer

$x=173/7$

How do you solve sqrt(7x-4)=13sqrt(7x-4)=13?