How do you solve $\sqrt{7 x - 4} = 13$ $sqrt(7x-4)=13$ ?

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Answer 1 · 2017-05-08T13:07:30

$7 x - 4 = 169$ $7x-4=169$ or $x = \frac{173}{7}$ $x=173/7$

Get rid of square root of the first term by taking 2nd power of both sides:

Now you will have

${{(7 x - 4)}^{0.5}}^{2} = 13^{2}$ ${(7x-4)^0.5}^2=13^2$

$7 x - 4 = 13 \cdot 13$ $7x-4=13*13$

$7 x = 169 + 4$ $7x=169+4$

$7 x = 173$ $7x=173$

$x = \frac{173}{7}$ $x=173/7$

This is your answer

$x = \frac{173}{7}$ $x=173/7$

How do you solve √7x−4=13sqrt(7x-4)=13?