How do you solve #sqrt(7x-4)=13#?

Question

1022 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-08T13:07:30

#7x-4=169# or #x=173/7#

Get rid of square root of the first term by taking 2nd power of both sides:

Now you will have

#{(7x-4)^0.5}^2=13^2#

#7x-4=13*13#

#7x=169+4#

#7x=173#

#x=173/7#

This is your answer

#x=173/7#