How do you solve $sqrt(6x+1) = 3sqrt(x)-1$ ?

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Answer 1 · 2016-05-24T09:14:20

$x=0$ or $x=4$

Squaring both sides of $sqrt(6x+1)=3sqrtx-1$ , we get

$6x+1=9x+1-6sqrtx$

or $6sqrtx=9x+1-6x-1$

or $6sqrtx=3x$

or $2sqrtx=x$ - now squaring this

$4x=x^2$ or $x^2-4x=0$

or $x(x-4)=0$

Hence $x=0$ or $x=4$

How do you solve sqrt(6x+1) = 3sqrt(x)-1 sqrt(6x+1) = 3sqrt(x)-1?