How do you solve $sqrt(4x+8)+8 = 1$ ?

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Answer 1 · 2018-05-06T11:06:49

$x = 10.25$

$sqrt(4x+8) = 1 - 8$
$sqrt(4x+8) = -7$
$(sqrt(4x+8))^2 = (-7)^2$
$4x+8 = 49$
$4x = 41$
$(4x) / 4= 41 / 4$
$x = 41 / 4$
$x = 10.25$

Answer 2 · 2018-05-06T12:26:31

$"no solution"$

$"isolate "sqrt(4x+8)" by subtracting 8 from both sides"$

$rArrsqrt(4x+8)=-7$

$sqrt(4x+8)>=0to x inRR$

$rArr"there is no solution"$

How do you solve sqrt(4x+8)+8 = 1sqrt(4x+8)+8 = 1?