How do you solve $sqrt(4x+5)=x$ ?

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Answer 1 · 2016-08-02T03:34:00

$(sqrt(4x + 5))^2 = x^2$

$4x + 5 = x^2$

$0 = x^2 - 4x - 5$

$0 = (x - 5)(x + 1)$

$x = 5 and -1$

However, checking in the original equation, we find that only $x = 5$ works. Hence, the solution set is ${5}$ .

Hopefully this helps!

How do you solve sqrt(4x+5)=xsqrt(4x+5)=x?