How do you solve sqrt(4m^2-3m+2)-2m-5=04m23m+22m5=0?

1 Answer
Feb 10, 2017

m=1m=1

Explanation:

If we separate out the root and put everything else on the other side of the = we can 'get rid' of the root by squaring both sides.

Write as sqrt(4m^2-3m+2)=2m+54m23m+2=2m+5

Square both sides

4m^2-3m+2" "=" "(2m+5)^24m23m+2 = (2m+5)2

cancel(4m^2)-3m+2" "=" "cancel(4m^2)+20m+25

20m+3m=2-25

23m=23

Divide both sides by 23

m=1