How do you solve #sqrt(4m^2-3m+2)-2m-5=0#?

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Answer 1 · 2017-02-10T21:29:26

#m=1#

If we separate out the root and put everything else on the other side of the = we can 'get rid' of the root by squaring both sides.

Write as #sqrt(4m^2-3m+2)=2m+5#

Square both sides

#4m^2-3m+2" "=" "(2m+5)^2#

#cancel(4m^2)-3m+2" "=" "cancel(4m^2)+20m+25#

#20m+3m=2-25#

#23m=23#

Divide both sides by 23

#m=1#