How do you solve #sqrt(3k-11)=sqrt(5-k)#?

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Answer 1 · 2017-02-12T11:39:31

#k=4#

Given:

#sqrt(3k-11) = sqrt(5-k)#

Square both sides (noting that this may introduce an extraneous solution) to get:

#3k-11 = 5-k#

Add #11+k# to both sides to get:

#4k = 16#

Divide both sides by #4# to get:

#k = 4#

Check:

#sqrt(3*color(blue)(4)-11) = sqrt(1) = sqrt(5-color(blue)(4))#