How do you solve $\sqrt{2 x - 1} = \sqrt{x + 4}$ $sqrt(2x-1)=sqrt(x+4)$ ?

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How do you solve $\sqrt{2 x - 1} = \sqrt{x + 4}$ $sqrt(2x-1)=sqrt(x+4)$ ?

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Answer 1 · 2016-07-29T14:48:28

$x = 5$ $x=5$

Explanation:

$\sqrt{2 x - 1} = \sqrt{x + 4}$ $sqrt(2x-1)=sqrt(x+4)$
Squaring both sides
$2 x - 1 = x + 4$ $2x-1=x+4$
or
$2 x - x = 4 + 1$ $2x-x=4+1$
or
$x = 5$ $x=5$

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How do you solve $\sqrt{2 x - 1} = \sqrt{x + 4}$ $sqrt(2x-1)=sqrt(x+4)$ ?

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How do you solve $\sqrt{2 x - 1} = \sqrt{x + 4}$ $sqrt(2x-1)=sqrt(x+4)$ ?