How do you solve $\sqrt{2 x + 1} + \sqrt{2 x + 6} = 5$ $sqrt(2x+1)+sqrt(2x+6)=5$ ?

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Answer 1 · 2017-02-09T01:34:16

x= 3/2

Try move one square to the other side: $\sqrt{2 x + 1} = 5 - \sqrt{2 x + 6}$ $sqrt(2x+1)=5-sqrt(2x+6)$
Take a square and you will get: $2 x + 1 = 25 + 2 x + 6 - 10 \cdot \sqrt{2 x + 6}$ $2x+1=25+2x+6-10*sqrt(2x+6)$
And now the 2xs are cancelled on both sides, rearrange and you will get: $10 \cdot \sqrt{2 x + 6} = 30$ $10*sqrt(2x+6)=30$
Now the equation is simple, take a square on both sides and you will get the answer.

How do you solve √2x+1+√2x+6=5sqrt(2x+1)+sqrt(2x+6)=5?