How do you solve #sqrt(2a^2-121)=a# and check your solution?

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Answer 1 · 2017-01-26T21:44:20

#a=+-11#

#a=sqrt(2a^2-121)#

Square both sides

#a^2=2a^2-121#

Minus #a^2# and add #121# to both sides

#a^2=121#

Square root both sides

#a=+-sqrt(121)=+-11#

Now to check:

#a=sqrt(2xx11^2-121)=sqrt(242-121)=sqrt(121)=+-11#