How do you solve $sinxcosx=1/2$ ?

1 Answer

Dec 27, 2016

$x= pi/4 + kpi$

Explanation:

$sin x .cos x = 1/2$
Replace in the equation (sin x.cos x) by $(sin 2x)/2$ -->
$(sin 2x)/2 = 1/2$
$sin 2x = 1$
Trig unit circle -->
$2x = pi/2 + 2kpi$
$x = pi/4 + kpi$

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