How do you solve $sin x - tan x = 0$ $sinx-tanx=0$ ?

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How do you solve $sin x - tan x = 0$ $sinx-tanx=0$ ?

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Answer 1 · 2018-06-05T00:36:08

$x = k π$ $x = kpi$
$x = 2 k π$ $x = 2kpi$

Explanation:

sin x - tan x = 0
$sin x - (\frac{sin x}{cos x}) = 0$ $sin x - (sinx/cos x) = 0$
sin x.cos x - sin x = 0
sin x(cos x - 1) = 0
Either factor should be zero.
a. sin x = 0
Unit circle gives:
x = 0, $x = π, and x = 2 π$ $x = pi, and x = 2pi$
General answer: $x = k π$ $x = kpi$
b. cos x - 1 = 0 --> cos x = 1
$x = 0 + 2 k π = 2 k π$ $x = 0 + 2kpi = 2kpi$

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How do you solve $sin x - tan x = 0$ $sinx-tanx=0$ ?

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How do you solve $sin x - tan x = 0$ $sinx-tanx=0$ ?