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How do you solve $sinx=sqrt3/2$ ?

1 Answer

Apr 2, 2018

$x = 60$

Explanation:

$sin 0 =sqrt(0)/2$ , $sin 0 = 0$

$sin 30 =sqrt(1)/2$ , $sin 30 = 1/2$

$sin 45 = sqrt(2)/2$

$sin 60 =sqrt(3)/2$

$sin 90 =sqrt(4)/2$ , $sin 90 = 1$

For the exact cos values simply reverse the order of 0, 1, 2, 3 and 4 in the square root sign

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