How do you solve sinx=sqrt2/2 and find all exact general solutions?

1 Answer
Binayaka C.
Oct 10, 2016

General solution: x= (2n pi+pi/4) and x=(2n pi+(3pi)/4)

Explanation:

sinx=sqrt2/2 ;. We know sin(pi/4)=sqrt2/2 and sin(pi-pi/4)=sqrt2/2 or sin ((3pi)/4)=sqrt2/2 In interval 0<=x<=2pi ; x= pi/4 , (3pi)/4
General solution x= (2n pi+pi/4) and x=(2n pi+(3pi)/4) Where
n is an integer.[Ans]

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