How do you solve $sinx+3=2.0816$ in the interval [0,360]?

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Answer 1 · 2017-06-04T19:25:23

$x= 246.69^@, 293.31^@$

$sinx+3=2.0816$

$sinx= -0.9184$

$x = -66.69$

We know that $sinx$ is periodic every $360^@$ , so the first valid value of $x$ in our range is $360+(-66.69)=293.31^@$ .

We also know that, for $x, sinx = sin(180-x)$ .

So another valid value of $x$ is $180-(-66.69)= 246.69^@$

How do you solve sinx+3=2.0816sinx+3=2.0816 in the interval [0,360]?