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How do you solve $sinx=-1/2$ ?

1 Answer

bp · Stefan V.

Dec 19, 2016

$x= (7pi)/6 ,(11pi)/6$

Explanation:

$Sin x$ is negative in the $"III"^"rd"$ and $"IV"^"th"$ quadrants. Since

$sin pi/6=1/2$

$sin x$ would be $-1/2$ for $x= pi +pi/6$ and for $x = 2pi -pi/6$ .

The Principal solution is this

$x= (7pi)/6, (11pi)/6$

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