How do you solve $Sin (4theta) - Sin(6theta) = 0$ ?

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Answer 1 · 2016-06-27T07:47:34

$theta = (npi)/5, n=0, +-1, +-2, +-3, ...$

$sin 4theta-sin 6theta = -2 sin theta sin 5theta=0$

So sin theta = 0#, giving

$theta =npi, n=0, +-1, +-2, +-3, ..$ and

$sin 5theta=0$ giving $theta=npi)$ , and so,

$theta=(npi )/5, n=0, +-1, +-2, +-3, ..$

The second set includes the first, as a subset.

How do you solve Sin (4theta) - Sin(6theta) = 0Sin (4theta) - Sin(6theta) = 0?