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How do you solve $sin^2x + 2sinx - 3 = 0$ ?

1 Answer

May 3, 2015

Let sin x = t,

$f(t) = t^2 + 2t - 3 = 0$

Since a + b + c = 0, one real root is t = 1 and the other: $t = c/a = -3.$

$Solve: t = sin x = 1 = sin (pi/2) -> x = pi/2$

The solution t = -3 is rejected.

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