How do you solve $sin (θ/2) = √3/2$ from $[0,2pi]$ ?

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Answer 1 · 2015-07-25T03:49:34

Solve $sin x/2 = sqrt3/2$ $(0, 2pi)$

Ans: $(2pi)/3 and (4pi)/3$

Trig table gives -> $sin x/2 = sqrt3/2$ --> $x/2 = (pi)/3$ -> $x = (2pi)/3$

Trig unit circle gives another $x/2 = (2pi)/3$ -> $x = (4pi)/3$

How do you solve sin (θ/2) = √3/2sin (θ/2) = √3/2 from [0,2pi][0,2pi]?