How do you solve secxtanx=2/3?

1 Answer
Nov 12, 2016

pi/6, (5pi)/6

Explanation:

sec xtan x = 2/3
(1/cos x)(sin x/(cos x)) = 2/3
Cross multiply:
3sin x = 2 cos^2 x = 2(1 - sin^2 x) = 2 - 2sin^2 x
Solve this quadratic equation in sin x:
2sin^2 x + 3sin x - 2 = 0.
Use the improved quadratic formula (Socratic Search)
D = d^2 = b^2 - 4ac = 9 + 16 = 25 --> d = +- 5
There are 2 real roots:
sin x = -b/(2a) +- d/(2a) = -3/4 +- 5/4
sin x = - 8/4 = - 2 (rejected because < - 1) and
sin x = 2/4 = 1/2
Trig table and unit circle -->
sin x = 1/2 --> arc x = pi/6 and arc x = (5pi)/6
For general answers, add (k2pi)