How do you solve $sec θ = 4$ $sec theta = 4$ ?

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How do you solve $sec θ = 4$ $sec theta = 4$ ?

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Answer 1 · 2018-05-26T16:42:27

$θ = - arccos (\frac{1}{4}) + 2 k π$ $theta=-arccos(1/4)+2kpi$ or $θ = arccos (\frac{1}{4}) + 2 k π$ $theta=arccos(1/4)+2kpi$

Explanation:

Since
$sec (x) = \frac{1}{cos (x)}$ $sec(x)=1/cos(x)$
we have to solve that
$cos (θ) = \frac{1}{4}$ $cos(theta)=1/4$
We get the solutions like above.

Answer 2 · 2018-05-26T17:56:04

$t = \pm 75^{\circ} 52 + k 360^{\circ}$ $t = +- 75^@52 + k360^@$

Explanation:

sec t = 4 --> $cos t = \frac{1}{sec t} = \frac{1}{4} = 0.25$ $cos t = 1/(sec t) = 1/4 = 0.25$
Calculator and unit circle give 2 solutions for t:
$t = \pm 75^{\circ} 52 + k 360^{\circ}$ $t = +- 75^@52 + k360^@$

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How do you solve $sec θ = 4$ $sec theta = 4$ ?

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How do you solve sec theta = 4secθ=4sec theta = 4?

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How do you solve $sec θ = 4$ $sec theta = 4$ ?