How do you solve #sec^2 x sin^2 x - sec^2 x = -1#?

1 Answer

May 31, 2018

#f(x) = sec^2 x.sin^2 x - sec^2 x#
#f(x) = sec^2 x(sin^2 x - 1)#
Note:
#sec^2 x = 1/(cos^2 x)#
#sin^2 x - 1 = - cos^2 x#
Therefor,
#f(x) = - cos^2 x/(cos^2 x) = - 1#. Proved.

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How do you solve #sec^2 x sin^2 x - sec^2 x = -1#?

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