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How do you solve #sec^2 x-3sec x+2=0#?

1 Answer

Aug 18, 2015

Solve #sec^2 x - 3sec x + 2 = 0#

Explanation:

Solve the quadratic equation:
#sex^2 x - 3sec x+ 2 = 0.#
Since a + b + c = 0, use the shortcut. Two real roots: sec x = 1 and #sec x = c/a = 2#

a. #sec x = 1/cos x = 1 #--> #cos x = 1# --> #x = 0# and #x = 2pi#

b. #sec x = 1/cos x = 2# --> #cos x = 1/2# --># x = +- pi/3#

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