How do you solve $sec^2 x-3sec x+2=0$ ?

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Answer 1 · 2015-08-18T04:19:43

Solve $sec^2 x - 3sec x + 2 = 0$

Solve the quadratic equation:
$sex^2 x - 3sec x+ 2 = 0.$
Since a + b + c = 0, use the shortcut. Two real roots: sec x = 1 and $sec x = c/a = 2$

a. $sec x = 1/cos x = 1$ --> $cos x = 1$ --> $x = 0$ and $x = 2pi$

b. $sec x = 1/cos x = 2$ --> $cos x = 1/2$ --> $x = +- pi/3$

How do you solve sec^2 x-3sec x+2=0sec^2 x-3sec x+2=0?