How do you solve #root4(x-7)=2#?

Question

1211 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-13T22:38:04

#x=23#

Given:

#root(4)(x-7) = 2#

Raise both sides to the #4#th power to get:

#x-7 = 16#

Add #7# to both sides to find:

#x = 23#

Check:

#root(4)(23 - 7) = root(4)(16) = root(4)(2^4) = 2#