How do you solve $root3(x+4)=root3(2x-5)$ ?

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Answer 1 · 2017-03-29T15:08:40

$x = 9$

$root(3)(x + 4) = root(3)(2 x -5)$

power of 3 to both sides.
$(root(3)(x + 4))^3 =( root(3)(2 x -5))^3$

$x + 4 =2 x -5$
$9 = x$

How do you solve root3(x+4)=root3(2x-5)root3(x+4)=root3(2x-5)?