How do you solve root3(7n-8)=3 and find any extraneous solutions?

1 Answer
A08
Aug 18, 2016

n=5 and there are no extraneous solutions.

Explanation:

root3(7n-8)=3

Taking cube of both sides we get
(root3(7n-8))^3=3^3
=>7n-8=27

Rearranging and solving for n
7n=27+8
n=35/7=5
Insert n=5 in original equation. We see that the equation holds good. We have a solution and there are no extraneous solutions.

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