How do you solve $r^2+3r-2=0$ using the quadratic formula?

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Answer 1 · 2018-06-09T08:16:15

$color(purple)(r = (-3 + sqrt 17) / 2, (-3 -sqrt(17)) / 2$

Quadratic Formula $x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$a = 1, b = 3, c = -2$

$r = (-3 +- sqrt(9 + 8) ) / 2$

$color(purple)(r = (-3 + sqrt 17) / 2, (-3 -sqrt(17)) / 2$

How do you solve r^2+3r-2=0 r^2+3r-2=0 using the quadratic formula?