Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #p( p + 5) = 14#?

1 Answer

Oct 16, 2017

#p=2,p=-7#

Explanation:

#p(p+5)=14#

# :.p^2+5p=14#

#:.p^2+5p-14=0#

#:.(p-2)(p+7)=0#

#:.p=2# or #p=-7#

~~~~~~~~~~~~~~~~

check;-

substitute #p=2#

#:.2(2+5)=14#

#:.14=14#

substitute #p=-7#

#;.-7(-7+5)=14#

#:.-7(-2)=14#

#:.14=14#

Related questions

See all questions in Multi-Step Equations with Like Terms

Impact of this question

1142 views around the world

You can reuse this answer
Creative Commons License