How do you solve $\frac{n}{7 - n} + \frac{3}{5} = 1$ $n/(7-n)+3/5=1$ ?

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Answer 1 · 2018-04-17T10:24:30

$n = 2$ $n = 2$

$\frac{n}{7 - n} + \frac{3}{5} = 1$ $n/(7-n) + 3/5 = 1$

$n/(7-n) + color(red)(cancel(color(black)(3/5) -3/5)) = 1 color(red)(-3/5)$

$n/(7-n) = 5/5 - 3/5$

$n/(7-n) = 2/5$

We can cross multiply here.

$n xx 5 = 2 xx (7-n)$

$5n color(red)( +2n)= 14 color(red)(cancel(color(black)(-2n) +2n))$

$(color(red)(cancel(7))n)/color(red)(cancel(7)) = 14/color(red)(7)$

$color(blue)(n = 2)$

How do you solve n/(7-n)+3/5=1n7−n+35=1n/(7-n)+3/5=1?