How do you solve $n^2+8=80$ ?

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How do you solve $n^2+8=80$ ?

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Answer 1 · 2017-02-13T20:12:45

$n=+-6sqrt2$

Explanation:

$"Isolate "n^2"$ by subtracting 8 from both sides of the equation.

$n^2cancel(+8)cancel(-8)=80-8$

$rArrn^2=72$

Take the $color(blue)"square root"$ of both sides.

$sqrt(n^2)=+-sqrt72$

$rArrn=+-sqrt72$

Simplifying $sqrt72$

$n=+-(sqrt(36xx2))$

$color(white)(n)=+-(sqrt36xxsqrt2)$

$rArrn=+-6sqrt2$

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How do you solve $n^2+8=80$ ?

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How do you solve n^2+8=80n^2+8=80?

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How do you solve $n^2+8=80$ ?