How do you solve $m^2 + m + 1 = 0$ using the quadratic formula?

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Answer 1 · 2018-07-09T02:57:23

$m=(-1+sqrt(3)i)/2$ , $(-1-sqrt(3)i)/2$

Solve:

$m^2+m+1=0$

This is a quadratic equation in standard form:

$ax^2+bx+c$ ,

where:

$a=1$ , $b=1$ , $c=1$

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Substitute $m$ for $x$ . Plug in the known values.

$m=(-1+-sqrt(1^2-4*1*1))/(2*1)$

$m=(-1+-sqrt(-3))/2$

Simplify.

$m=(-1+-sqrt(3)i)/2$

$m=(-1+sqrt(3)i)/2$ , $(-1-sqrt(3)i)/2$

How do you solve m^2 + m + 1 = 0 m^2 + m + 1 = 0 using the quadratic formula?