Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #log x+log 20=2#?

1 Answer

Nov 29, 2015

#x=5#

Explanation:

#log(x)+log(20) = log(20x)#

So, if #log(x)+log(20)=2#
then
#color(white)("XXX")log(20x)=2#

#rArrcolor(white)("XX")10^(log(20x)) = 10^2#

#rArrcolor(white)("XX")20x = 100#

#rArrcolor(white)("XX")x=5#

Related questions

See all questions in Logarithmic Models

Impact of this question

5096 views around the world

You can reuse this answer
Creative Commons License