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How do you solve #log_(x-2) (9) =2#?

1 Answer

May 6, 2016

#x=5#

Explanation:

#log_(x-2) 9=2#

#log_a b=c" "a^c=b#

#9=(x-2)^2#

#3^2=(x-2)^2#

#3=x-2#

#x=3+2#

#x=5#

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