How do you solve log- m+2 = 4 ?

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Answer 1 · 2018-04-19T00:32:24

$m = - 100$ $m=-100$

I am assuming that we have:

$log (- m) + 2 = 4$ $log(-m)+2=4$

$\Rightarrow {log}_{10} (- m) = 2$ $=>log_10(-m)=2$

Remember that:

If ${log}_{a} (b) = c$ $log_a(b)=c$ , then $b = a^{c}$ $b=a^c$

$\Rightarrow - m = 10^{2}$ $=>-m=10^2$

$\Rightarrow - m = 100$ $=>-m=100$

$\Rightarrow m = - 100$ $=>m=-100$