How do you solve log- m+2 = 4 ?

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Answer 1 · 2018-04-19T00:32:24

#m=-100#

I am assuming that we have:

#log(-m)+2=4#

#=>log_10(-m)=2#

Remember that:

If #log_a(b)=c#, then #b=a^c#

#=>-m=10^2#

#=>-m=100#

#=>m=-100#