How do you solve ${log}_{b} 64 = 3$ $log_b64=3$ ?

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Answer 1 · 2016-11-10T14:07:32

Logarithms can be converted to exponential form using ${log}_{a} (b) = n \to a^{n} = b$ $log_a(b) = n-> a^n = b$ . So,for this problem, we have:

$b^{3} = 64$ $b^3 = 64$

Equating exponents:

$b^{3} = 4^{3}$ $b^3 = 4^3$

$b = 4$ $b = 4$

Hopefully this helps!

How do you solve logb64=3log_b64=3?