How do you solve log_b121=2?

1 Answer
r3cebarnett
Nov 5, 2016

+-11, see explanation.

Explanation:

if you have a^b = c, logarithms go log_ac = b. That's just a thing that you need to know, I'm not quite sure how to explain that, but if we apply it to the logarithm in the problem...

log_b121=2 -> b^2=121.

And from here you just take the square root of both sides and get +-11. It's plus or minus because 11^2 and (-11)^2 equal 121. (Negative multiplied by a negative equals a positive).

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