How do you solve ${log}_{3} x = 4$ $log_3x=4$ ?

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How do you solve ${log}_{3} x = 4$ $log_3x=4$ ?

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Answer 1 · 2018-06-26T14:35:38

$x = 81$ $x=81$

Explanation:

$using the law of logarithms$ $"using the "color(blue)"law of logarithms"$

$∙ x {log}_{b} x = n \Leftrightarrow x = b^{n}$ $•color(white)(x)log_b x=nhArrx=b^n$

${log}_{3} x = 4 \Rightarrow x = 3^{4} = 81$ $log_3x=4rArrx=3^4=81$

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How do you solve ${log}_{3} x = 4$ $log_3x=4$ ?

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How do you solve ${log}_{3} x = 4$ $log_3x=4$ ?