How do you solve #log_3x=4#?
1 Answer
Jun 26, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#log_3x=4rArrx=3^4=81#
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#log_3x=4rArrx=3^4=81#