How do you solve $log_3 x=2$ ?

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Answer 1 · 2016-10-09T06:51:41

$x=9$

We can write log problems two different ways:

$log_(a)b=c$

$a^c=b$

So we can take the original question:

$log_3x=2$

and rewrite it to:

$3^2=x=9$

How do you solve log_3 x=2log_3 x=2?