How do you solve ${log}_{25} n = \frac{3}{2}$ $log_25 n=3/2$ ?

Question

2105 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-21T19:11:23

We know that if ${log}_{a} n = m$ $log_a n = m$ , then $n = a^{m}$ $n = a^m$ .

$n = 25^{\frac{3}{2}}$ $n = 25^(3/2)$

$n = {(\sqrt{25})}^{3}$ $n = (sqrt(25))^3$

$n = {(5)}^{3}$ $n = (5)^3$

$n = 125$ $n = 125$

Hopefully this helps!

How do you solve log_25 n=3/2log25n=32log_25 n=3/2?