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How do you solve #log_10(x^2+1)=1#?

1 Answer

Nov 19, 2016

#x=+-3#

Explanation:

#log_ab=c=>a^c=b#

#log_10(x^2+1)=1=>10^1=x^2+1#

#x^2+1=10#

#x^2=9#
#x=sqrt9=+-3#

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