# How do you solve lnx-ln(x+2)=1?

$\ln \left(x\right) < \ln \left(x + 2\right)$
$\Rightarrow \ln \left(x\right) - \ln \left(x + 2\right) < 0$
$. : \ln \left(x\right) - \ln \left(x + 2\right) \ne + 1$ for any value of $x$