How do you solve $\frac{(x - 4)}{3} = \frac{9}{12}$ $\frac { ( x - 4) } { 3} = \frac { 9} { 12}$ ?

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How do you solve $\frac{(x - 4)}{3} = \frac{9}{12}$ $\frac { ( x - 4) } { 3} = \frac { 9} { 12}$ ?

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Answer 1 · 2018-02-21T00:34:26

$x = \frac{25}{4}$ $x = 25/4$

Explanation:

Firstly, multiply both sides by $12$ $12$ .

$\frac{12 (x - 4)}{3} = 9$ $(12(x-4))/3 = 9$

$(cancel(12)(x-4))/cancel(3) = 9$

$4(x-4) = 9$

Divide $4$ on both sides.

$x-4 = 9/4$

And finally, add 4 to both sides.

$x= 9/4 + 4$

If you wish so, you can make them have the same denominator :

$x = 9/4 + 4/1$

$x= 9/4 + 16/4$

$color(blue)(x=25/4$

I hope that helps!

Answer 2 · 2018-02-21T00:39:18

$x=25/4$

Explanation:

$(x-4)/3=9/12$

Cross multiply

$(x-4)(12)=9*3$

Distributive property

$(12)(x)+(12)(-4)=27$

$12x-48=27$

$12x=27+48$

$12x=75$

$x=75/12$

$x=25/4$

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How do you solve $\frac{(x - 4)}{3} = \frac{9}{12}$ $\frac { ( x - 4) } { 3} = \frac { 9} { 12}$ ?

2 Answers

Explanation:

Explanation:

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How do you solve \frac { ( x - 4) } { 3} = \frac { 9} { 12}(x−4)3=912\frac { ( x - 4) } { 3} = \frac { 9} { 12}?

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How do you solve $\frac{(x - 4)}{3} = \frac{9}{12}$ $\frac { ( x - 4) } { 3} = \frac { 9} { 12}$ ?