How do you solve $\frac{2}{3} n + 3 \frac{1}{3} = 9 \frac{1}{3}$ $\frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}$ ?

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Answer 1 · 2018-04-30T20:42:44

$n = 9$ $n = 9$

First you want to have like terms on the same side. Subtract 3 1/3 from both sides.

$\frac{2}{3} n = 6$ $2/3n = 6$

Now multiply both sides by the reciprocal of 2/3, 3/2.

$n = 9$ $n = 9$

Check:
$(\frac{2}{3} \cdot 9) + 3 \frac{1}{3} = 9 \frac{1}{3}$ $(2/3 * 9) + 3 1/3 = 9 1/3$

$6 + 3 \frac{1}{3} = 9 \frac{1}{3}$ $6 + 3 1/3 = 9 1/3$

$9 \frac{1}{3} = 9 \frac{1}{3}$ $9 1/3 = 9 1/3$

Answer 2 · 2018-04-30T20:42:53

$n = 9$ $n=9$

First, subtract $3 \frac{1}{3}$ $3 1/3$ from $9 \frac{1}{3}$ $9 1/3$ to get $6$ $6$ and from the left side. This should give you the equation

$\frac{2}{3} n = 6$ $2/3 n =6$

In order to solve for $n$ $n$ , we multiply both sides by the reciprocal of $\frac{2}{3}$ $2/3$ , which is $\frac{3}{2}$ $3/2$ .

$6$ $6$ multiplied by $\frac{3}{2}$ $3/2$ is

$6 \cdot \frac{3}{2} = \frac{18}{2} = 9$ $6 * 3/2 = 18/2 = 9$

so

$\frac{2}{3} n \cdot \frac{3}{2} = 9$ $2/3n * 3/2 = 9$

How do you solve \frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}23n+313=913\frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}?