How do you solve for y in #5y - q = 20#?

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Answer 1 · 2016-03-28T06:34:27

#y=(q+20)/5#

We start from the given equation

#5y-q=20#

Transpose #q# to the right of the equation

#5y=20+q#

Divide both sides by 5

#(5y)/5=(20+q)/5#

#(cancel5y)/cancel5=(20+q)/5#

#y=(q+20)/5#

God bless....I hope the explanation is useful.