How do you determine the amount of liquid a paper cone can hold with a 1.5-inch diameter and a 5-inch height if the volume formula is given by $V o l u m e = \frac{π r^{2} (h)}{3}$ $Volume = (pi r^2 (h))/3$ , where r= the radius , and h= the height of the cone?

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Answer 1 · 2018-05-30T01:49:48

$\approx 2.945$ $approx 2.945$ cubic inches of liquid

We are given the volume of a cone is:

Volume $= \frac{1}{3} π r^{2} h$ $= 1/3pir^2h$

We are told that our cone has a diameter of 1.5 inches and a height of 5 inches.

Radius $(r) = \frac{1}{2} \times$ $(r) = 1/2 xx$ Diameter

$:. r = 1.5/2 = 0.75$ inches

Applying the formula above:

Volume $=1/3xxpixx0.75^2 xx5$

$approx 1/3xx 3.14159 xx 0.5625 xx5$

$approx 2.945$ cubic inches

Hence our cone can hold approximately 2.945 cubic inches of liquid.

How do you determine the amount of liquid a paper cone can hold with a 1.5-inch diameter and a 5-inch height if the volume formula is given by Volume = (pi r^2 (h))/3Volume=πr2(h)3Volume = (pi r^2 (h))/3 , where r= the radius , and h= the height of the cone?