How do you solve for y in #-3x+5y=-10#?

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Answer 1 · 2015-04-11T09:36:31

#-3x+5y=-10#

As we need to solve for #y#, we transpose #-3x# to the right hand side to get

#5y=-10 + 3x#

We divide both sides by 5

#(cancel(5)y)/cancel(5)=(-10 + 3x)/5#

#y = - 10/ 5 + (3x)/5#

#y = - 2 + (3x)/5#

#color(green)(y = (3x)/5 - 2#